Nettet21. apr. 2024 · Explanation: [ (2ex + 3e–x)/ (3ex + 4e–x)] = [ (2e2x + 3)/ (3e2x + 4)] ∴ 2e2x + 3 = A (3e2x + 4) + B (6 ∙ e2x) ∴ 2 = 3A + 6B & 3 = 4A ⇒ A = (3/4) ∴ 6B = 2 – 3A = 2 – (9/4) = [ (– 1)/4] ⇒ B = – (1/24) ∴ I = ∫ [(2e2x + 3)/ (3e2x + 4)]dx = ∫ [( {+ (3/4) (3e2x + 4) – (1/24) (6 ∙ e2x)dx})/ (3e2x + 4)]dx = (3/4)∫dx – (1/24)∫ [ (6 ∙ e2x)/ (3e2x + 4)]dx Nettet28. sep. 2024 · From this it follows that: e x2 = e g (x) Let’s set f (x) = e x. Then, because g (x) = x 2, the function e x2 can be written as a composite function of f (x) and g (x). f (x) = e x f (g (x)) = e g (x) (but g (x) = x 2) Therefore, f (g (x)) = e x2 Let’s define this composite function as F (x): F (x) = f (g (x)) = e x2
Calcular la integral int((x^2-2x^5)e^(-x))dx SnapXam
NettetSolution Verified by Toppr Correct option is A) ∫( x+4x+2) 2e xdx =∫(1− x+42) 2e xdx =∫(1+ (x+4) 24 − x+44)e xdx =∫(1+ (x+4) 24)e xdx−∫x+44 e xdx =e x+4[e x( x+4−1)−∫e xx+4−1 dx]−∫x+44 e xdx =( x+4x)e x+C Solve any question of Integrals with:- Patterns of problems > Was this answer helpful? 0 0 Similar questions ∫e x( x 2+x+1x 4+x 2+1)dx= Medium NettetDerivatives Derivative Applications Limits Integrals Integral Applications Integral Approximation Series ODE Multivariable Calculus Laplace Transform Taylor/Maclaurin … matthews paint mpc
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NettetThe integral of a constant is the constant times the variable of integration: ∫ 2 e 3 d x = 2 x e 3 The result is: x 2 2 + 2 x e 3 − 3 tan ( x) Add the constant of integration: x 2 2 + 2 x e 3 − 3 tan ( x) + c o n s t a n t The answer is: x 2 2 + 2 x e 3 − 3 tan ( x) + c o n s t a n t The answer (Indefinite) [src] NettetMinus 2 times xe to the x minus e to the x. And if we want, now is a good time to put our plus C. And of course, we can simplify this. This is equal to x squared. I like to keep the same colors. This is equal to x squared e to the x. You distribute the negative 2. You get minus 2xe to the x plus 2e to the x, and then finally, plus C. And we're ... NettetThe Integral Calculator supports definite and indefinite integrals (antiderivatives) as well as integrating functions with many variables. You can also check your answers! … matthews paint retrieval